若1/X-1/Y=3,则2X+XY-2Y/X-2XY-Y=?
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若1/X-1/Y=3,则2X+XY-2Y/X-2XY-Y=?
若1/X-1/Y=3,则2X+XY-2Y/X-2XY-Y=?
若1/X-1/Y=3,则2X+XY-2Y/X-2XY-Y=?
1/X-1/Y=3
(2X+XY-2Y) / (X-2XY-Y)
分子分母同除以XY:
= (2/Y+1-2/X) / (1/Y-2-1/X)
= {1-2(1/X-1/Y)} / {-2-(1/X-1/Y)}
= {1-2*3} / {-2-3}
= (-5) / (-5)
=1
最简单的方法
(2x+3xy-2y)/(x-2xy-y)
分子分母同时除以xy,得:
=[(2/y-2/x)+3]/[(1/y-1/x)-2]
=[-2(1/x-1/y)+3)/[-(1/x-1/y)-2]
=(-6+3)/(-3-2)
=3/5
你提问的问题不全,可以有很多答案,肯定有条件限制的
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