若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 14:03:16
若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为
x){ѽ83O|:OvL9Q@(jcfr~ѹ@ R{:eTOv6TqH 1&l 4 #@FFa@ γO>tOTXS_VH$ف< 

若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为
若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为

若sin(π/4-α)=5/13,且α(0,π/2),则cos2α/cos(π/4+α)为
cos(pai/4+α)=sin(π/4-α)=5/13,cos2α=sin2(π/4-α)=2sin(π/4-α)cos(π/4-α)=2*5/13*12/13=120/169 ,故待求式=(120/169)/(5/13)=24/13