计算(x²+4x-12/x²+x+1)(x²-1/x²-4x+4)(2-x/x²+5x-6)的值
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![计算(x²+4x-12/x²+x+1)(x²-1/x²-4x+4)(2-x/x²+5x-6)的值](/uploads/image/z/1627298-26-8.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%88x%26%23178%3B%2B4x-12%2Fx%26%23178%3B%2Bx%2B1%EF%BC%89%EF%BC%88x%26%23178%3B-1%2Fx%26%23178%3B-4x%2B4%EF%BC%89%EF%BC%882-x%2Fx%26%23178%3B%2B5x-6%EF%BC%89%E7%9A%84%E5%80%BC)
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计算(x²+4x-12/x²+x+1)(x²-1/x²-4x+4)(2-x/x²+5x-6)的值
计算(x²+4x-12/x²+x+1)(x²-1/x²-4x+4)(2-x/x²+5x-6)的值
计算(x²+4x-12/x²+x+1)(x²-1/x²-4x+4)(2-x/x²+5x-6)的值
=[(x+6)(x-2)/(x²+x+1)][(x+1)(x-1)/(x-2)²]{(2-x)/[(x+6)(x-1)]}
=-(x+1)/(x²+x+1)
题目没问题吧?