如果(3x²-2)-(3x²-y)=-2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值是
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![如果(3x²-2)-(3x²-y)=-2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值是](/uploads/image/z/1628322-42-2.jpg?t=%E5%A6%82%E6%9E%9C%283x%26%23178%3B-2%29-%283x%26%23178%3B-y%29%3D-2%2C%E9%82%A3%E4%B9%88%E4%BB%A3%E6%95%B0%E5%BC%8F%28x%2By%29%2B3%28x-y%29%EF%BC%8D4%EF%BC%88x%EF%BC%8Dy%EF%BC%8D2%EF%BC%89%E7%9A%84%E5%80%BC%E6%98%AF)
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如果(3x²-2)-(3x²-y)=-2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值是
如果(3x²-2)-(3x²-y)=-2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值是
如果(3x²-2)-(3x²-y)=-2,那么代数式(x+y)+3(x-y)-4(x-y-2)的值是
(3x²-2)-(3x²-y)=-2
3x²-2-3x²+y=-2
y-2=-2
y=0
(x+y)+3(x-y)-4(x-y-2)
=x+y+3x-3y-4x+4y+8
=2y+8
=0+8
=8
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(3x²-2)-(3x²-y)=-2
3x²-2-3x²+y=-2
y=0
(x+y)+3(x-y)-4(x-y-2)
=x+y+3x-3y-4x+4y+8
=2y+8
=0+8
=8
将前式括号打开,3x^2被消掉了,可知y=0。那么将后式中括号打开,原式=x+y+3x-3y-4x+4y+8=2y+8=8
所以值为8