求y=(x^2-3x+2)/(x^2+2x-3)的值域.
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求y=(x^2-3x+2)/(x^2+2x-3)的值域.
求y=(x^2-3x+2)/(x^2+2x-3)的值域.
求y=(x^2-3x+2)/(x^2+2x-3)的值域.
y=(x²-3x+2)/(x²+2x-3)
.=[(x-1)(x-2)]/[(x-1)(x+3)]
.=(x-2)/(x+3)
则值域是:{y|y≠1且y≠-1/4}
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