3(x+4)²=x²-16
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3(x+4)²=x²-16
3(x+4)²=x²-16
3(x+4)²=x²-16
3(x+4)²=x²-16
3x²+24x+48=x²-16
2x²+24x+64=0
2(x²+12x+32)=0
2(x+4)(x+8)=0
x1=-4,x2=-8
解
3(x+4)²=x²-16
3(x+4)²-(x²-16)=0
3(x+4)²-(x+4)(x-4)=0
(x+4)(3x+12-x+4)=0
(x+4)(2x+16)=0
∴x=-4
或x=-8