已知x²-5x+1=0,求√(x²+1/x²-2)的值
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已知x²-5x+1=0,求√(x²+1/x²-2)的值
已知x²-5x+1=0,求√(x²+1/x²-2)的值
已知x²-5x+1=0,求√(x²+1/x²-2)的值
x²-5x+1=0
两边同除以x得:x - 5 + 1/x = 0
x+1/x = 5
(x+1/x)²=25
x²+2+1/x²=25
x²+1/x²=23
√(x²+1/x²-2) = √(23-2) = √21