作业帮(1/3)^[log(1/2)^(x^2-3x+1)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/03 09:39:05
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(1/3)^[log(1/2)^(x^2-3x+1)]
(1/3)^[log(1/2)^(x^2-3x+1)]
(1/3)^[log(1/2)^(x^2-3x+1)]
由原式可得(1/3)^[log(1/2)^(x^2-3x+1)]<(1/3)^0
所以log(1/2)^(x^2-3x+1)>0
又因为底数是1/2,所以
0
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