|x-y-2|+|3x-6y-7|+(3y+3z-4)的平方=0,x=?,y=?,z=?
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|x-y-2|+|3x-6y-7|+(3y+3z-4)的平方=0,x=?,y=?,z=?
|x-y-2|+|3x-6y-7|+(3y+3z-4)的平方=0,x=?,y=?,z=?
|x-y-2|+|3x-6y-7|+(3y+3z-4)的平方=0,x=?,y=?,z=?
|x-y-2|+|3x-6y-7|+(3y+3z-4)的平方=0
所以
x-y-2=0 (1)
3x-6y-7=0 (2)
3y+3z-4=0 (3)
(1)×6-(2)
6x-12-3x+7=0
3x=-5
所以
x=-5/3
y=x-2=-11/3
z=(4-3y)/3=5
|x-y-2|+|3x-6y-7|+(3y+3z-4)的平方=0
x-y-2=0, (1)
3x-6y-7=0, (2)
3y+3z-4=0, (3)
由(1)(2)可得:x=5/3,y=-1/3
代入(3)得:z=5/3
等式左边的每一项都是非负的,它们的和等于0那么每一项都应该是0,从而得到关于x,y,z的三个方程组成方程组,解之既得。
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