(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 19:32:48
x){èQr#]
]C{:@HY@)] ̩I*'O~
4kiqAbn wr
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(4x)=(1/2)x-1-(5/2)y
求(3x^+y^-5xy)-【2x^-(-4xy-y^+7x^)】=?
求(3x^+y^-5xy)-【2x^-(-4xy-y^+7x^)】=?
已知x-xy=10,xy-y=2,则x-y=( ),-2xy+x+y=( ).
(X-3xy+4xy-y)-[-2x-2(xy-3/2xy)-y]+6xy的过程
3)(3x²y-xy²+2xy)÷二分之一xy 4) (x-3)×(x+3)-(x+10×(x+3)
1.已知x+y=-4,xy=3,求5(2分之1xy+2y)+[6x-(2xy+y-3x)]的值2.已知(x+3)^2+|x-y+10|=0求代数式5x^2y-[2x^2y-(3xy-xy^2)-3x^2]-2xy^2-y^2的值
若(3xy+2)+|7-x-y|=0,求代数式(5xy+10y)-[-5x-(4xy-2y+3x)]的值.
(xy-x²)÷(x²-2xy+y²/xy)×(x-y/x²)
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
((xy+2)(xy-2)-2x^2y^2+4)除以xy,其中x=10,y=-1/5((xy+2)(xy-2)-2x^2 y^2+4)化简求值
(12x^2y-8xy^2+16xy)/-3x+2y-4=?
(12x^2y-8xy^2+16xy)/-3x+2y-4=?
整式乘法..1.3xy(x²y-xy²+xy)-xy²(2x²-xy+2x)2.(x-1)(x²-4x+3)-x(x²-5x+2)
(-4xy的三次方)×(-2x)=() 3xy(2x平方y-三分之一xy平方)=()
已知x+y=4,xy=-2,求代数式3(xy+2y)-(xy-6x)
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
已知x^2+9y^2-2x-6y+2=0,求{-(xy/(x-y)^2}^4*(y^2-xy/x)^3*x^4/y^10/(x/xy-y^2)^5的值
计算:3xy(x²y-xy²+xy)-xy²(2x-xy+2x)