(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 19:32:48
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
x){èQr#] ]C{:@HY@)] ̩I*'O~ 4kiqAbnwr

(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y

(2x∧2-4x-10xy)/(?)=(1/2)x-1-(5/2)y
(2x∧2-4x-10xy)/(4x)=(1/2)x-1-(5/2)y