已知x+根号(x²-1)+1/(x+根号x²-1)=10,求x²+根号(x四次方-1)+1/(x²-根号x四次这是我写的,看不懂上面的人看这个
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![已知x+根号(x²-1)+1/(x+根号x²-1)=10,求x²+根号(x四次方-1)+1/(x²-根号x四次这是我写的,看不懂上面的人看这个](/uploads/image/z/1637241-33-1.jpg?t=%E5%B7%B2%E7%9F%A5x%2B%E6%A0%B9%E5%8F%B7%EF%BC%88x%26%23178%3B-1%EF%BC%89%2B1%2F%EF%BC%88x%2B%E6%A0%B9%E5%8F%B7x%26%23178%3B-1%EF%BC%89%3D10%2C%E6%B1%82x%26%23178%3B%2B%E6%A0%B9%E5%8F%B7%EF%BC%88x%E5%9B%9B%E6%AC%A1%E6%96%B9-1%EF%BC%89%2B1%2F%EF%BC%88x%26%23178%3B-%E6%A0%B9%E5%8F%B7x%E5%9B%9B%E6%AC%A1%E8%BF%99%E6%98%AF%E6%88%91%E5%86%99%E7%9A%84%EF%BC%8C%E7%9C%8B%E4%B8%8D%E6%87%82%E4%B8%8A%E9%9D%A2%E7%9A%84%E4%BA%BA%E7%9C%8B%E8%BF%99%E4%B8%AA)
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已知x+根号(x²-1)+1/(x+根号x²-1)=10,求x²+根号(x四次方-1)+1/(x²-根号x四次这是我写的,看不懂上面的人看这个
已知x+根号(x²-1)+1/(x+根号x²-1)=10,求x²+根号(x四次方-1)+1/(x²-根号x四次
这是我写的,看不懂上面的人看这个
已知x+根号(x²-1)+1/(x+根号x²-1)=10,求x²+根号(x四次方-1)+1/(x²-根号x四次这是我写的,看不懂上面的人看这个
x+根号(x²-1)+1/(x+根号x²-1)
x+根号(x²-1)+(x-√(x^2-1))/(x+根号x²-1)(x-√(x^2-1))
=x+根号(x²-1)+x-根号(x²-1)
=2x=10
x=5
x²+根号(x四次方-1)+1/(x²-根号(x四次-1))
=x²+根号(x四次方-1)+(x^2-√(x^4-1))/(x^2+根号x^4-1)(x^2-√(x^^4-1))
=x²+根号(x四次方-1)+(x^2-√(x^4-1))
=2x^2
=50