x²+4x+y²-6y+13=0则x+y=?
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x²+4x+y²-6y+13=0则x+y=?
x²+4x+y²-6y+13=0则x+y=?
x²+4x+y²-6y+13=0则x+y=?
即(x²+4x+4)+(y²-6y+9)=0
(x+2)²+(y-3)²=0
所以x+2=y-3=0
x=-2,y=3
所以x+y=1
x²+4x+y²-6y+13=0
(x+2)^2+(y-3)^2=0
x+2=0,y-3=0
x=-2,y=3
x+y=-2+3=1
∵x²+4x+y²-6y+13=0
∴﹙x+2﹚²+﹙y-3﹚²=0
∴x+2=0, y-3=0
∴x=﹣2, y=3
∴x+y=1
一个个好聪明