{(x+2y)(x-2y)+[2(x-y)]²}÷6x=?

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{(x+2y)(x-2y)+[2(x-y)]²}÷6x=?
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{(x+2y)(x-2y)+[2(x-y)]²}÷6x=?
{(x+2y)(x-2y)+[2(x-y)]²}÷6x=?

{(x+2y)(x-2y)+[2(x-y)]²}÷6x=?
原式=(x²-4y²+4x²-8xy+4y²)÷6x
=(5x²-8xy)÷6x
=(5x-8y)/6

{(x+2y)(x-2y)+[2(x-y)]²}÷6x
=(x²-4y²+4x²+4y²-8xy)÷6x
=(5x²-8xy)÷6x
=(5x-8y)/6