已知(x²+y²)²-(x²+y²)-12=0,则x²+y²的值是
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已知(x²+y²)²-(x²+y²)-12=0,则x²+y²的值是
已知(x²+y²)²-(x²+y²)-12=0,则x²+y²的值是
已知(x²+y²)²-(x²+y²)-12=0,则x²+y²的值是
(x²+y²)²-(x²+y²)-12=0
用十字相乘法得
(x²+y²-4)(x²+y²+3)=0
解得
x²+y²=-3(舍去)
x²+y²=4
把x2+y2当成一个整体,解得4或-3,因为平方大于等于0,所以等于4