[x-(x+1分之2x)]÷x²-1分之x²-2x+1
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[x-(x+1分之2x)]÷x²-1分之x²-2x+1
[x-(x+1分之2x)]÷x²-1分之x²-2x+1
[x-(x+1分之2x)]÷x²-1分之x²-2x+1
[x-(x+1分之2x)]÷x²-1分之x²-2x+1
=[x-(2x/x+1)]×[(x+1)(x-1)/(x-1)²]
=[(x²-x)/(x+1)]×[(x+1)/(x-1)]
=[x(x-1)/(x+1)]×[(x+1)/(x-1)]
=x