△ABC中,AB=AC,点D、E、F分别在AB、BC、AC边上,且BE=CF,BD=CE(1)求证:△DEF是等腰三角形.(1)求证:△DEF是等腰三角形.(2)当∠A=40°时,求∠DEF得度数.(3)△DEF可能是等腰三角行吗?为什么
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![△ABC中,AB=AC,点D、E、F分别在AB、BC、AC边上,且BE=CF,BD=CE(1)求证:△DEF是等腰三角形.(1)求证:△DEF是等腰三角形.(2)当∠A=40°时,求∠DEF得度数.(3)△DEF可能是等腰三角行吗?为什么](/uploads/image/z/1646772-60-2.jpg?t=%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2C%E7%82%B9D%E3%80%81E%E3%80%81F%E5%88%86%E5%88%AB%E5%9C%A8AB%E3%80%81BC%E3%80%81AC%E8%BE%B9%E4%B8%8A%2C%E4%B8%94BE%3DCF%2CBD%3DCE%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3DEF%E6%98%AF%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3DEF%E6%98%AF%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2.%EF%BC%882%EF%BC%89%E5%BD%93%E2%88%A0A%3D40%C2%B0%E6%97%B6%2C%E6%B1%82%E2%88%A0DEF%E5%BE%97%E5%BA%A6%E6%95%B0.%EF%BC%883%EF%BC%89%E2%96%B3DEF%E5%8F%AF%E8%83%BD%E6%98%AF%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E8%A1%8C%E5%90%97%3F%E4%B8%BA%E4%BB%80%E4%B9%88)
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