已知:在三角形ABC中,AC=BC,∠CAB=∠CBA=45°,CD是∠ACB的平分线,点E是AB边上一点.(1)直线BF垂直于直线CE于点F交CD于点G(如图8),求证AE=CG.(2)直线AH垂直于直线CE,垂足为点H,交CD的延长线于点M(如图
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 21:16:56
![已知:在三角形ABC中,AC=BC,∠CAB=∠CBA=45°,CD是∠ACB的平分线,点E是AB边上一点.(1)直线BF垂直于直线CE于点F交CD于点G(如图8),求证AE=CG.(2)直线AH垂直于直线CE,垂足为点H,交CD的延长线于点M(如图](/uploads/image/z/1647021-21-1.jpg?t=%E5%B7%B2%E7%9F%A5%3A%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAC%3DBC%2C%E2%88%A0CAB%3D%E2%88%A0CBA%3D45%C2%B0%2CCD%E6%98%AF%E2%88%A0ACB%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%2C%E7%82%B9E%E6%98%AFAB%E8%BE%B9%E4%B8%8A%E4%B8%80%E7%82%B9.%EF%BC%881%EF%BC%89%E7%9B%B4%E7%BA%BFBF%E5%9E%82%E7%9B%B4%E4%BA%8E%E7%9B%B4%E7%BA%BFCE%E4%BA%8E%E7%82%B9F%E4%BA%A4CD%E4%BA%8E%E7%82%B9G%EF%BC%88%E5%A6%82%E5%9B%BE8%29%2C%E6%B1%82%E8%AF%81AE%3DCG.%EF%BC%882%EF%BC%89%E7%9B%B4%E7%BA%BFAH%E5%9E%82%E7%9B%B4%E4%BA%8E%E7%9B%B4%E7%BA%BFCE%2C%E5%9E%82%E8%B6%B3%E4%B8%BA%E7%82%B9H%2C%E4%BA%A4CD%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8E%E7%82%B9M%28%E5%A6%82%E5%9B%BE)
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