已知int a[ ] ={10,9,8,7,6},*p=a; 则*(p+1)*(p+2)[2]的值是C++中根据内存分配的区域来区分,内存的分配方式有哪几种C++的new与C的malloc有什么主要联系和区别

已知int a=10,b=15;,表达式!a int a=2; int f(int a); {return (a)++;} main() {int s=0; {int a=5; s+=f(&&a);} s+=f(&&a); printf(%da=2;int f(int a);{return (a)++;}main(){int s=0;{int a=5;s+=f(&&a);}s+=f(&&a);printf(%d ,s);}执行的输出结果是（）A 10 B 9 C 7 D 8 #include void main(){ int b=3;int a; int arr[]={6,7,8,9,10}; int *ptr=arr; *(ptr++)+=123;#include using namespace std;void main(){ int b=3;int a; int arr[]={6,7,8,9,10}; int *ptr=arr; *(ptr++)+=123; printf(%d,%d ,*(p void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i #define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i 矩阵相加（C++）#include using namespace std; const int rows=3;const int cols=3;void matrixadd(int *,int *,int *,int,int);int main(){int a[rows][cols]={{1,3,5},{7,8,11},{13,15,17}};int b[rows][cols]={{9,8,7},{6,5,4},{3,2,1}};int c[rows][cols]={0 int[][]myarray=new int[][]{new int[]{1,2.3},}new int[]{4,5,6,7},new int{8,9,10,11,12},new int[]{-1.int[][]myarray=new int[][]{new int[]{1,2.3},}new int[]{4,5,6,7},new int[]{8,9,10,11,12},new int[]{-1.0}}; myarray[2][1]=______ #include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a; 其中p=(int**)a;是什么意思啊 #include stdio.h void fun(int a,int b) { int t; t=a,a=b,b=t; } main() { int c[10]={1,2,3,4,5,6,7#include stdio.hvoid fun(int a,int b){int t;t=a,a=b,b=t;}main(){int c[10]={1,2,3,4,5,6,7,8,9,0},i;for(i=0;i #include int b=2; int fun(int *k) {b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}, #define N 20 fun(int a[],int n,int m) { int i; for(i=m;i>=n;i--) a[i+1]=a[i]; return a[a+1]; } main#define N 20fun(int a[],int n,int m){ int i;for(i=m;i>=n;i--)a[i+1]=a[i];return a[a+1];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i 求助C语音的作业,我不是学这个的已知： int i=13,j=17,a=4,x=1,y=2,z=3,d;写出下列表达式的值.(1) 10%a(2) i!=j(3) !(i+j)(4) ++a+a(5) 3/5||i= =j(6) d=i>j?i:j(7) –x&&++y||z++(8) 4+7%3*(int)(4+5.6)%2(9) (float)(2+4)/2+(int)4.6%(int 10．已知int a[3][3]={ 1,2,3,4,5,6,7,8,9};,则*(*(a+2)+1) 的值是___________. 应用函数、数组、指针求数组中的最大值、最小值、平均值. 我作出了一个但是总是出错?#includeint max(int *p);int min(int *q);double averrage(int *n);void main(){ int a[10]={1,2,3,4,5,6,7,8,9,10}; int k,z; double s; 下列程序的输出结果是#define N 20void fun (int a[ ],int n,int m){int i,j;for (i=m;i>n;i--)a[i+1]=a[i];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i int a[ ][3]={1,2,3,4,5,6,7,8,9,10,11,12}；int*p=a；求 *(*(a+2)+2)的含义(或值 #include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8}#include int b=2; int fun(int*k) { b=*k+b;return(b);} main() {int a[10]={1,2,3,4,5,6,7,8},i;for(i=2;i