在三角形abc中,角abc的角平分线与角acb的外交平分线交于d,过d作de∥bc交ac于f,j交ab于e.求证:ef=be-cfok
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![在三角形abc中,角abc的角平分线与角acb的外交平分线交于d,过d作de∥bc交ac于f,j交ab于e.求证:ef=be-cfok](/uploads/image/z/1649251-19-1.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2abc%E4%B8%AD%2C%E8%A7%92abc%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%E4%B8%8E%E8%A7%92acb%E7%9A%84%E5%A4%96%E4%BA%A4%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E4%BA%8Ed%2C%E8%BF%87d%E4%BD%9Cde%E2%88%A5bc%E4%BA%A4ac%E4%BA%8Ef%2Cj%E4%BA%A4ab%E4%BA%8Ee.%E6%B1%82%E8%AF%81%EF%BC%9Aef%3Dbe-cfok)
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