Y=根号下(X的平方-8X+20) + 根号下(X的平方+1) =根号下[(x-4)^2+(2-0)^2]+根号下[(x-0)^2+(2-1)^2] 我们以把这个问题看成是点(4,0)和点(0,1)到直线y=2的某一点距离之和,先找出点(0,1)到直线y=2对
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 07:01:37
![Y=根号下(X的平方-8X+20) + 根号下(X的平方+1) =根号下[(x-4)^2+(2-0)^2]+根号下[(x-0)^2+(2-1)^2] 我们以把这个问题看成是点(4,0)和点(0,1)到直线y=2的某一点距离之和,先找出点(0,1)到直线y=2对](/uploads/image/z/1672540-52-0.jpg?t=Y%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%28X%E7%9A%84%E5%B9%B3%E6%96%B9-8X%2B20%29+%2B+%E6%A0%B9%E5%8F%B7%E4%B8%8B%28X%E7%9A%84%E5%B9%B3%E6%96%B9%2B1%29+%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%EF%BC%88x-4%EF%BC%89%5E2%2B%282-0%29%5E2%5D%2B%E6%A0%B9%E5%8F%B7%E4%B8%8B%5B%28x-0%29%5E2%2B%282-1%29%5E2%5D+%E6%88%91%E4%BB%AC%E4%BB%A5%E6%8A%8A%E8%BF%99%E4%B8%AA%E9%97%AE%E9%A2%98%E7%9C%8B%E6%88%90%E6%98%AF%E7%82%B9%EF%BC%884%2C0%EF%BC%89%E5%92%8C%E7%82%B9%EF%BC%880%2C1%EF%BC%89%E5%88%B0%E7%9B%B4%E7%BA%BFy%3D2%E7%9A%84%E6%9F%90%E4%B8%80%E7%82%B9%E8%B7%9D%E7%A6%BB%E4%B9%8B%E5%92%8C%2C%E5%85%88%E6%89%BE%E5%87%BA%E7%82%B9%EF%BC%880%2C1%EF%BC%89%E5%88%B0%E7%9B%B4%E7%BA%BFy%3D2%E5%AF%B9)
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