π-6+| π - 6 |=( ).若（A+3）²+| 4 - 6 |=0,那么A²与2B的大小关系是（ ）.

设a属于(π,2π),若tan(a+π/6)=2,则cos(π/6-a)= cos7/6π=? cos7/6π=? cos7π/6=? 若α∈(π/2,π),sin(α+π/6)=3/5,sinα= cosπ/6=(),sinπ=() 若sin(x+6/π)=1/3,求sin(7π/6+x)+cos2(5π/6-x) 若sin(π/6-a)=根号3/3,则sin(7π/6-a)= 若sin(π/6-α)=根号3/3,则,sin(7π/6-α)= 若sin(π/6-a)=a,则sin(5π/6+a)= 若cos(π/6-a)=根号3,那么cos(5π/6+a)= 2(-cos(π/6)+isin(π/6）) =2(cos(π-π/6)+isin(π-π/6))为什么是π-π/6呢,谁能告诉我 设a∈(π),若tan(α+π/6)=2,则cos(π/6-2a)的值为设α∈(π),若tan(α+π/6)=2,则cos(π/6-2α)的值为 π/6 π/6 π/6 sin4/3π*cos11/6π*tan3/4π= (sin2π/3+cos11π/6)tan7π/4=