若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=
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![若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=](/uploads/image/z/1674301-13-1.jpg?t=%E8%8B%A5%28x%26%23178%3B-1%29%28x%26%23178%3B%2Bmx%2Bn%29%3Dx%E7%9A%843%E6%AC%A1%E6%96%B9-6x%26%23178%3B%2B11x-6%2C%E5%88%99m%3D+n%3D%E8%8B%A5%28x%26%23178%3B-1%29%28x%26%23178%3B%2Bmx%2Bn%29%3Dx%E7%9A%843%E6%AC%A1%E6%96%B9-6x%26%23178%3B%2B11x-6%2C%E5%88%99m%3D+n%3D)
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若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=
若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=
若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=
若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=若(x²-1)(x²+mx+n)=x的3次方-6x²+11x-6,则m= n=
(x-1)((x²+mx+n)=x³+mx²+nx-x²-mx-n=x³+(m-1)x²+(n-m)x-n=x³-6x²+11x-6
所以n=6,m=-5