如图,△ABC中,AB=AC,∠BAC=90°, ∠ABD=∠ACE,CE=BD. 求证:(1)△ADE也为等腰直角三角形,(2)BD⊥CE.
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![如图,△ABC中,AB=AC,∠BAC=90°, ∠ABD=∠ACE,CE=BD. 求证:(1)△ADE也为等腰直角三角形,(2)BD⊥CE.](/uploads/image/z/1692386-26-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2C%E2%88%A0BAC%3D90%C2%B0%2C+%E2%88%A0ABD%3D%E2%88%A0ACE%2CCE%3DBD.+%E6%B1%82%E8%AF%81%EF%BC%9A%281%29%E2%96%B3ADE%E4%B9%9F%E4%B8%BA%E7%AD%89%E8%85%B0%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%2C%282%29BD%E2%8A%A5CE.)
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