∫1/[√x+三次根号x]dx要具体步骤 谢谢

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∫1/[√x+三次根号x]dx要具体步骤  谢谢
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∫1/[√x+三次根号x]dx要具体步骤 谢谢
∫1/[√x+三次根号x]dx
要具体步骤 谢谢

∫1/[√x+三次根号x]dx要具体步骤 谢谢
令六次根号x=t
则√x=t^3
三次根号x=t^2
dx=6t^5dt
∫1/[√x+三次根号x]dx
=∫6t^5/(t^3+t^2)dt
=∫6t^3/(t+1)dt
=6[∫(t^3+1)/(t+1)dt-∫1/(t+1)dt]
=6[∫(t^2-t+1)dt-∫1/(t+1)dt]
=6[t^3/3-t^2/2+t-ln(t+1)]
=2t^3-3t^2+6t-6ln(t+1)
=2√x-3三次根号x+6六次根号x-6ln(六次根号x+1)