已知函数f(x)=sin^2x+根号3sinx×sin(x+π/2)(1)f(x)的最小正周期(2)求f(x)的单调递增区间(3)求f(x)在区间【0,2π/3】的取值范围

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 04:56:46
已知函数f(x)=sin^2x+根号3sinx×sin(x+π/2)(1)f(x)的最小正周期(2)求f(x)的单调递增区间(3)求f(x)在区间【0,2π/3】的取值范围
xSNAG#F511&J2e3 F%qC ⒰{NՍcQaz{tM ƽyv {=~T_wk2fy XÏ_snmOUuQ7VCkc\Pgr 20@0" Y@ac0 )_hV1ЮB1N]$}[I6W-`~@u욕C8 „6%:h^Zs=UH\}*΁ /tmQkУ>vFEq",i`/n$* G$%[ Wo$~vS6c>"/9 1Iyq&җ*[;s(pc-\sz0W Z"7JV-ftf xǘXm6C+[A/c~ش

已知函数f(x)=sin^2x+根号3sinx×sin(x+π/2)(1)f(x)的最小正周期(2)求f(x)的单调递增区间(3)求f(x)在区间【0,2π/3】的取值范围
已知函数f(x)=sin^2x+根号3sinx×sin(x+π/2)
(1)f(x)的最小正周期
(2)求f(x)的单调递增区间
(3)求f(x)在区间【0,2π/3】的取值范围

已知函数f(x)=sin^2x+根号3sinx×sin(x+π/2)(1)f(x)的最小正周期(2)求f(x)的单调递增区间(3)求f(x)在区间【0,2π/3】的取值范围
“数理答疑团”为您解答,希望对你有所帮助.
(1)f(x)的最小正周期 π
f(x)=sin^2x+√3sinx×sin(x+π/2)
=(1-cos2x)/2 -√3sinxcosx
=1/2 -(cos2x)/2 -√3/2 sin2x
=1/2 -sin(2x+π/6)
(2)求f(x)的单调递增区间:[kπ+π/6,kπ+2π/3]
2kπ+π/2≤2x+π/6≤2kπ+3π/2 得:kπ+π/6≤x≤kπ+2π/3
(3)求f(x)在区间【0,2π/3】的取值范围
f(x)在区间【0,π/6】单调递减,取值范围:[-1/2,0]
f(x)在区间【π/6,2π/3】单调递增,取值范围:[-1/2,3/2]
所以:f(x)在区间【0,2π/3】的取值范围:[-1/2,3/2]
手机提问的朋友在客户端右上角评价点【满意】即可.