满足sin(x+sinx)=cos(x-cosx)的锐角x为几满足sin(x+sinx)=cos(x-cosx)的锐角x为几

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/02 07:03:30
满足sin(x+sinx)=cos(x-cosx)的锐角x为几满足sin(x+sinx)=cos(x-cosx)的锐角x为几
x){{m3t&@> /OxcdiI*': tݓ@9M[> F`;=m]o=`*H:*@:* : H0}@d O|b˞[lN'z0Q,# oBTb@+L|I G[Q] dHH<1@?';y@̄D \0+uth|v9+1F 1l'{?e{ϧ{ڿn`|K< D%%VU)zI)z9yE9EA)ށUI!a>%eAEUNfE奆IٙI)naAA9ɉΎU%N^aH

满足sin(x+sinx)=cos(x-cosx)的锐角x为几满足sin(x+sinx)=cos(x-cosx)的锐角x为几
满足sin(x+sinx)=cos(x-cosx)的锐角x为几
满足sin(x+sinx)=cos(x-cosx)的锐角x为几

满足sin(x+sinx)=cos(x-cosx)的锐角x为几满足sin(x+sinx)=cos(x-cosx)的锐角x为几
cos(X-cosX)=sin(π/2-X+cosX)
带入原式
sin(x+sinx)=sin(π/2-x+cosx)
x+sinx=π/2-x+cosx
sinx-cosx=π/2-2x
对于原式左侧有
sinx-cosx
=√2(√2/2*sinx-√2/2cosx)
=√2(sinxcosπ/4-cosxsinπ/4)
=√2sin(x-π/4)
∴ √2sin(x-π/4)=π/2-2x
将x=π/4带入,易得原方程两侧都等于0
∴满足原方程的x∈(0,π/2)存在且x=π/4

你这量词用的..你可以去这里看看http://zhidao.baidu.com/link?url=rm1RidWgKQPa9zebTVLtkv1M_ROQpUrzQhiB36Orowu15bkibdFVRSQusXqiR8lP-1caUmXHpuCAza5tBuJVhq