设函数f(x)=Inx+In(2-x)+ax,(a>0).(1) 当a=1时,求f(x)的单调区间.(2) 若f(x)在(0,1]上的最大值为2) 若f(x)在(0,1]上的最大值为1/2求a的值
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![设函数f(x)=Inx+In(2-x)+ax,(a>0).(1) 当a=1时,求f(x)的单调区间.(2) 若f(x)在(0,1]上的最大值为2) 若f(x)在(0,1]上的最大值为1/2求a的值](/uploads/image/z/1698448-40-8.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3DInx%2BIn%282-x%29%2Bax%2C%28a%3E0%29.%EF%BC%881%EF%BC%89+%E5%BD%93a%3D1%E6%97%B6%2C%E6%B1%82f%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4.%EF%BC%882%EF%BC%89+%E8%8B%A5f%28x%29%E5%9C%A8%280%2C1%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA2%EF%BC%89+%E8%8B%A5f%28x%29%E5%9C%A8%280%2C1%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA1%2F2%E6%B1%82a%E7%9A%84%E5%80%BC)
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