1+2+3+.+(n-2)+(n-1)+n=?2+4+6+.+(2n-4)+(2n-2)+2n=?注:要写算式!
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/13 09:58:40
![1+2+3+.+(n-2)+(n-1)+n=?2+4+6+.+(2n-4)+(2n-2)+2n=?注:要写算式!](/uploads/image/z/1700553-57-3.jpg?t=1%2B2%2B3%2B.%2B%28n-2%29%2B%28n-1%29%2Bn%3D%3F2%2B4%2B6%2B.%2B%282n-4%29%2B%282n-2%29%2B2n%3D%3F%E6%B3%A8%EF%BC%9A%E8%A6%81%E5%86%99%E7%AE%97%E5%BC%8F%21)
x)3665yF&f a<]M06<ۼY/5>m|{mc~
d~O=
y
y
ME/.H̳ d
1+2+3+.+(n-2)+(n-1)+n=?2+4+6+.+(2n-4)+(2n-2)+2n=?注:要写算式!
1+2+3+.+(n-2)+(n-1)+n=?2+4+6+.+(2n-4)+(2n-2)+2n=?注:要写算式!
1+2+3+.+(n-2)+(n-1)+n=?2+4+6+.+(2n-4)+(2n-2)+2n=?注:要写算式!
1+2+3+.+(n-2)+(n-1)+n=?=(1/2) n (1 + n) 2+4+6+.+(2n-4)+(2n-2)+2n=?= n (1 + n)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简(n+1)(n+2)(n+3)
当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)...1=n
2^n/n*(n+1)
lim2^n +3^n/2^n+1+3^n+1
3(n-1)(n+3)-2(n-5)(n-2)
n(n+1)(n+2)(n+3)+1 因式分解
n(n+1)(n+2)(n+3)+1等于多少
lim(n+3)(4-n)/(n-1)(3-2n)
lim(n^3+n)/(n^4-3n^2+1)
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(2^n+3^n)^1
(n趋向无穷)
级数n/(n+1)(n+2)(n+3)和是多少
n*1+n*2+n*3+n*4.求公式