计算:(1)(√48-4√1/8)-(3√1/3-2√0.5)(2)√ab+2a√b/a+3b√a/b-5ab√1/ab(a>0,b>0)

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 01:29:06
计算:(1)(√48-4√1/8)-(3√1/3-2√0.5)(2)√ab+2a√b/a+3b√a/b-5ab√1/ab(a>0,b>0)
xSn1*RQxlmfmn'/@kPnDJUq7yy~ϛo7_wJ_߯t),!R&%&^ʈH Y\q!83C񔞬6)0+R?mEs: o떓;~Iwzi Aif-"Ǻ)i->ԧep/Œ b+ye97Be@p+ TJG  RBqMRQZ{-M=z*,xGjIv=γxg`-J&*8lK ,+jUN*dzjY  uD#1T#Ѡ

计算:(1)(√48-4√1/8)-(3√1/3-2√0.5)(2)√ab+2a√b/a+3b√a/b-5ab√1/ab(a>0,b>0)
计算:(1)(√48-4√1/8)-(3√1/3-2√0.5)
(2)√ab+2a√b/a+3b√a/b-5ab√1/ab(a>0,b>0)

计算:(1)(√48-4√1/8)-(3√1/3-2√0.5)(2)√ab+2a√b/a+3b√a/b-5ab√1/ab(a>0,b>0)
计算:
(1)(√48-4√1/8)-(3√1/3-2√0.5)
=(4√3-√2)-(√3-√2)
=4√3-√2-√3+√2
=3√3
(2)√ab-2a√b/a+3b√a/b-5ab√1/ab
=√ab-2√ab+3√ab-5√ab
=-3√ab

1、3√3
2、√ab