计算:(1/2+1/3+1/4+…+1//2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+1/4+…+1/2006)(1/2+1/3+…+1/2005)

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/09 06:55:06
计算:(1/2+1/3+1/4+…+1//2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+1/4+…+1/2006)(1/2+1/3+…+1/2005)
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计算:(1/2+1/3+1/4+…+1//2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+1/4+…+1/2006)(1/2+1/3+…+1/2005)
计算:(1/2+1/3+1/4+…+1//2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+1/4+…+1/2006)(1/2+1/3+…+1/2005)

计算:(1/2+1/3+1/4+…+1//2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+1/4+…+1/2006)(1/2+1/3+…+1/2005)
(1/2+1/3+1/4+…+1/2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+…+1/2006)(1/2+1/3+…1/2005)
=(1+1/2+1/3+1/4+…+1/2006)(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+…+1/2005)-(1+1/2+1/3+…+1/2006)(1/2+1/3+…1/2005)
=(1+1/2+1/3+1/4+…+1/2006)*1-(1+1/2+1/3+…+1/2005)
=1/2006
就这样答案为1/2006