已知整式14x+5-21x2(x的二次)=-2,求6x2(x的二次)-4x+5的值
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已知整式14x+5-21x2(x的二次)=-2,求6x2(x的二次)-4x+5的值
已知整式14x+5-21x2(x的二次)=-2,求6x2(x的二次)-4x+5的值
已知整式14x+5-21x2(x的二次)=-2,求6x2(x的二次)-4x+5的值
21x*x-14x=7
3x*x-2x=1
6x*x-4x=2
6x*x-4x+5=7
这样说你能明白吧.
7*3*2*x^2-7*2*x-7=0
2*3*2*x^2-2*2*x-2+7=7