1.要使二次根式√x+1有意义,x必须满足的条件是A.x≥1 B.x>-1 C.x≥-1 D.x>12.1 / √2 - 1 怎样化到最简?
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![1.要使二次根式√x+1有意义,x必须满足的条件是A.x≥1 B.x>-1 C.x≥-1 D.x>12.1 / √2 - 1 怎样化到最简?](/uploads/image/z/1721278-46-8.jpg?t=1.%E8%A6%81%E4%BD%BF%E4%BA%8C%E6%AC%A1%E6%A0%B9%E5%BC%8F%E2%88%9Ax%2B1%E6%9C%89%E6%84%8F%E4%B9%89%2Cx%E5%BF%85%E9%A1%BB%E6%BB%A1%E8%B6%B3%E7%9A%84%E6%9D%A1%E4%BB%B6%E6%98%AFA.x%E2%89%A51+B.x%EF%BC%9E-1+C.x%E2%89%A5-1+D.x%EF%BC%9E12.1+%2F+%E2%88%9A2+-+1+%E6%80%8E%E6%A0%B7%E5%8C%96%E5%88%B0%E6%9C%80%E7%AE%80%3F)
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1.要使二次根式√x+1有意义,x必须满足的条件是A.x≥1 B.x>-1 C.x≥-1 D.x>12.1 / √2 - 1 怎样化到最简?
1.要使二次根式√x+1有意义,x必须满足的条件是
A.x≥1 B.x>-1 C.x≥-1 D.x>1
2.1 / √2 - 1 怎样化到最简?
1.要使二次根式√x+1有意义,x必须满足的条件是A.x≥1 B.x>-1 C.x≥-1 D.x>12.1 / √2 - 1 怎样化到最简?
1.C x+1≥0
2.1 / √2 - 1 =√2 + 1 /(√2 - 1√2 + 1)=√2 + 1
1题:c 2题:√2 / 2- 1
1. C
2. √2 + 1
1.x+1≥0,(不等于0)
所以.x≥-1 ,故选C
2.1/√1=1/1=1
第二题是√(2 - 1)还是√2 - 1