(2x-3)(2x+3)=ax的平方+bx+ c 求a= b= c=
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(2x-3)(2x+3)=ax的平方+bx+ c 求a= b= c=
(2x-3)(2x+3)=ax的平方+bx+ c 求a= b= c=
(2x-3)(2x+3)=ax的平方+bx+ c 求a= b= c=
(2x-3)(2x+3)
=(2x)²-3²
=4x²-9
a=4
b=0
c=-9
a= 4 b=0 c= -9
(2x-3)(2x+3)=4x^2-9
所以a=4,b=0,c=-9
(2x-3)(2x+3)=4x²-9=ax²+bx+c,G故a=4,b=0,c=-9.