x²+y²-2x-4y+5=0,求½(x-1)²-xy的值
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x²+y²-2x-4y+5=0,求½(x-1)²-xy的值
x²+y²-2x-4y+5=0,求½(x-1)²-xy的值
x²+y²-2x-4y+5=0,求½(x-1)²-xy的值
由题中式条件等式可得:
(x-1)(x-1)+(y-2)(y-2)=0
所以,x=1,y=2
代入目标式中得到
1/2(x-1)(x-1)-xy=-2
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