x³+2x²-5x-6=0
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![x³+2x²-5x-6=0](/uploads/image/z/1730840-32-0.jpg?t=x%26%23179%3B%2B2x%26%23178%3B-5x-6%3D0)
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x³+2x²-5x-6=0
x³+2x²-5x-6=0
x³+2x²-5x-6=0
(x^3 + x^2) + (x^2 - 5x - 6) = x^2*(x+1) + (x+1)(x-6) = (x+1)(x^2 + x-6) (x+1)(x+3)(x-2) = 0
所以,它的解有:x = -1,x = -3,x = 2