(x+y)^2-3(x+y)+2=?
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(x+y)^2-3(x+y)+2=?
(x+y)^2-3(x+y)+2=?
(x+y)^2-3(x+y)+2=?
(x+y)^2-3(x+y)+2=(x+y-2)(x+y-1)
(x+y-1)(x+y-2)
(x+y)^2-3(x+y)+2
=(x+y-1)(x+y-2)
设x+y=t
则原式=t^2-3t+2
=(t-2)(t-1)
将 x+y=t代入
则原式=(x+y-2)(x+y-1)
(x+y-1)(x+y-2)
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
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