已知数列an的各项均为正数,前n项和为Sn,且满足2Sn=an^2+n-4,(1)求证an为等差数列 (2)求an的通项公式
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![已知数列an的各项均为正数,前n项和为Sn,且满足2Sn=an^2+n-4,(1)求证an为等差数列 (2)求an的通项公式](/uploads/image/z/1740874-58-4.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97an%E7%9A%84%E5%90%84%E9%A1%B9%E5%9D%87%E4%B8%BA%E6%AD%A3%E6%95%B0%2C%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BASn%2C%E4%B8%94%E6%BB%A1%E8%B6%B32Sn%3Dan%5E2%2Bn-4%2C%EF%BC%881%29%E6%B1%82%E8%AF%81an%E4%B8%BA%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97+%EF%BC%882%EF%BC%89%E6%B1%82an%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F)
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