化简求值:(2x²y-2xy²)-【(-3x²y²+3x²y)】,其中x=-1,y=1
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化简求值:(2x²y-2xy²)-【(-3x²y²+3x²y)】,其中x=-1,y=1
化简求值:(2x²y-2xy²)-【(-3x²y²+3x²y)】,其中x=-1,y=1
化简求值:(2x²y-2xy²)-【(-3x²y²+3x²y)】,其中x=-1,y=1
(2x²y-2xy²)-【(-3x²y²+3x²y)】
=2x²y-2xy²+3x²y²-3x²y
=-x²y-2xy²+3x²y²
当x=-1,y=1时
原式=-1+2+3=4