x²+4x分之x+4与x(x-5)-2(x-5)分之x-5化简我打错了,是通分、
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x²+4x分之x+4与x(x-5)-2(x-5)分之x-5化简我打错了,是通分、
x²+4x分之x+4与x(x-5)-2(x-5)分之x-5化简
我打错了,是通分、
x²+4x分之x+4与x(x-5)-2(x-5)分之x-5化简我打错了,是通分、
(x+4)/(x^2+4x)
=(x+4)/[x(x+4)]
=1/x
=(x-2)/[x(x-2)
(x-5)/[x(x-5)-2(x-5)]
=(x-5)/[(x-5)(x-2)]
=1/(x-2)
=x/[x(x-2)]
第一个为x
第二个为x-2
(x+4)/(x^2+4x)
=(x+4)/[x(x+4)]
=1/x
=(x-2) /[x(x-2) ] 就是化简后分子分母同时乘以(x-2)
(x-5)/[x(x-5)-2(x-5)]
=(x-5)/[(x-5)(x-2)]
=1/(x-2)
= x/[x(x-2) ] 就是化简后分子分母同时乘以x
这样分母相同就完成同分了
答案在图片上