lim 3n^2--2n+8 /4--n^2 n-->无穷大 的极限 求过lim 3n^2--2n+8 /4--n^2n-->无穷大的极限

lim(n+3)(4-n)/(n-1)(3-2n) lim(n^3+n)/(n^4-3n^2+1) 极限练习题lim(n->∞)[(n^2+3n-8)/(4n^2+2n+3)] lim[(4+7+...+3n+1)/(n^2-n)]= 求1.lim(3n-(3n^2+2n)/(n-1)) 2.lim(8+1/(n+1)) 3.lim根号n(根号(n+1)-根号(n-3)) lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?（n趋近于无穷大）为什么不成立? lim(n→∞) 2的2n次方-8/4n次方+3n次方 lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 lim(2^n+3^n)^1 (n趋向无穷) lim n趋向无穷大3n^3+n^2-3/4n^3+2n+1 lim(1/n^2+4/n^2+7/n^2+…+3n-1/n^2) lim(n→∞) (3^n-4^n)/(3^n+2×4^n),请计算, 求lim(n+1)(n+2)(n+3)/(n^4+n^2+1) 一道极限题,lim[n^2(2n+1)]/(n^3+n+4)n->∞ 1、lim n->无穷 根号[(n^4+n+1)-n^2]*(3n+4) lim(n→∞) 1/(n+1)-2/(n+1)+3/(n+1)-4/(n+1)+...+[(2n-1)/(n+1)]-[(2n)/(n-1)]求极限 大一微积分解答：lim(n→+∞)（2^n+4^n+6^n+8^n）^1/n=? lim（n->无穷大）（1^n+2^n+3^n+4^n）^1/n等于多少