通分:1/(x²+x),1/(x²-x)
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通分:1/(x²+x),1/(x²-x)
通分:1/(x²+x),1/(x²-x)
通分:1/(x²+x),1/(x²-x)
1/(x²+x)=1/[x(x+1)]=(x-1)/[x(x+1)(x-1)]
1/(x²-x)=1/[x(x-1)]=(x+1)/[x(x+1)(x-1)]