解一元二次方程,1.(2x+1)^2=3(2x+1) 2.3x^2-10x+6=0 3.√27-15√1/3+1/4√484.√5分之√20+√5-√1/3乘√12 5.(3√2-1)(1+3√2)-(3√2-1)^2 6.5√12除以1/5√50x1/5√3/2
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![解一元二次方程,1.(2x+1)^2=3(2x+1) 2.3x^2-10x+6=0 3.√27-15√1/3+1/4√484.√5分之√20+√5-√1/3乘√12 5.(3√2-1)(1+3√2)-(3√2-1)^2 6.5√12除以1/5√50x1/5√3/2](/uploads/image/z/1749773-29-3.jpg?t=%E8%A7%A3%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%2C1.%282x%2B1%29%5E2%3D3%282x%2B1%29+2.3x%5E2-10x%2B6%3D0+3.%E2%88%9A27-15%E2%88%9A1%2F3%2B1%2F4%E2%88%9A484.%E2%88%9A5%E5%88%86%E4%B9%8B%E2%88%9A20%2B%E2%88%9A5-%E2%88%9A1%2F3%E4%B9%98%E2%88%9A12+5.%283%E2%88%9A2-1%29%281%2B3%E2%88%9A2%EF%BC%89-%EF%BC%883%E2%88%9A2-1%EF%BC%89%5E2+6.5%E2%88%9A12%E9%99%A4%E4%BB%A51%2F5%E2%88%9A50x1%2F5%E2%88%9A3%2F2)
解一元二次方程,1.(2x+1)^2=3(2x+1) 2.3x^2-10x+6=0 3.√27-15√1/3+1/4√484.√5分之√20+√5-√1/3乘√12 5.(3√2-1)(1+3√2)-(3√2-1)^2 6.5√12除以1/5√50x1/5√3/2
解一元二次方程,1.(2x+1)^2=3(2x+1) 2.3x^2-10x+6=0 3.√27-15√1/3+1/4√48
4.√5分之√20+√5-√1/3乘√12
5.(3√2-1)(1+3√2)-(3√2-1)^2
6.5√12除以1/5√50x1/5√3/2
解一元二次方程,1.(2x+1)^2=3(2x+1) 2.3x^2-10x+6=0 3.√27-15√1/3+1/4√484.√5分之√20+√5-√1/3乘√12 5.(3√2-1)(1+3√2)-(3√2-1)^2 6.5√12除以1/5√50x1/5√3/2
1. (2x+1)^2=3(2x+1)
(2x+1)^2-3(2x+1)=0
(2x+1)(2x+1-3)=0
(2x+1)(2x-2)=0
x1=-1/2
x2=1
2. 3x^2-10x+6=0
公式法:
△=100-72=28
x=(10±2根号7)/6
x=(5±根号7)/3
以前学过的都还给老师了!现在的学生不好好学习,直接百度了
1. (2x+1)^2=3(2x+1)
(2x+1)^2-3(2x+1)=0
(2x+1)[(2x+1)-3]=0
(2x+1)(2x-2)=0
x=-1/2或1
2. 3x^2-10x+6=0
直接用公式法求(或配方法解)
3. √27-15√1/3+1/4√48
=3√3-5√3+√3
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1. (2x+1)^2=3(2x+1)
(2x+1)^2-3(2x+1)=0
(2x+1)[(2x+1)-3]=0
(2x+1)(2x-2)=0
x=-1/2或1
2. 3x^2-10x+6=0
直接用公式法求(或配方法解)
3. √27-15√1/3+1/4√48
=3√3-5√3+√3
=(3-5+1)√3
=-√3
4. √5分之√20+√5-√1/3乘√12
= 2+√5++6分子+√6
5. (3√2-1)(1+3√2)-(3√2-1)^2
=(3√2-1)[(1+3√2)-(3√2-1)]
=2(3√2-1)
=6√2-2
6. 5√12除以1/5√50x1/5√3/2
=3√10除以5(此题可能理解错误)
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