函数y=cos(3π/2-x)/cos(3π-x)最小正周期是

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/02 07:50:10
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
x){ھ t+4 ٜ]tgs?&H ]v6چS=XVA,}AYFE83B$1ydR4 @F 1K0l(C]~O'XHlctؖS6V:>T|V˳/xoӎ F:;mηu=1!a ҋ';vawӾOtYӀ ;n

函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
函数y=cos(3π/2-x)/cos(3π-x)最小正周期是

函数y=cos(3π/2-x)/cos(3π-x)最小正周期是
y=cos(3π/2-x)/cos(3π-x)
=cos(π+π/2-x)/cos(2π+π-x)
=-cos(π/2-x)/cos(π-x)
=sinx/-cosx
=-tanx
所以最小正周期T=π/W=π/1=π

y=sinxsin(3π/2-X)=sinx(-cosx)=(sin2x)/2
由y=Asin(ωx+φ)的性质得到A=1/2,ω=2 φ=0
T=2π/ω=π
即函数的最小正周期为π

原式=sinX*cosX=1/2sin2X;所以周期为π

o