数列{an}的首项a1=1,前n项和Sn与an之间满足an=2Sn^2/2Sn -1 (n>=2)在答案里写,由已知等式可知Sn(n>=2)不为零,我不明白它是怎么看出Sn不为零的,
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![数列{an}的首项a1=1,前n项和Sn与an之间满足an=2Sn^2/2Sn -1 (n>=2)在答案里写,由已知等式可知Sn(n>=2)不为零,我不明白它是怎么看出Sn不为零的,](/uploads/image/z/1753580-20-0.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E9%A6%96%E9%A1%B9a1%3D1%2C%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%E4%B8%8Ean%E4%B9%8B%E9%97%B4%E6%BB%A1%E8%B6%B3an%3D2Sn%5E2%2F2Sn+-1+%28n%3E%3D2%29%E5%9C%A8%E7%AD%94%E6%A1%88%E9%87%8C%E5%86%99%2C%E7%94%B1%E5%B7%B2%E7%9F%A5%E7%AD%89%E5%BC%8F%E5%8F%AF%E7%9F%A5Sn%28n%3E%3D2%29%E4%B8%8D%E4%B8%BA%E9%9B%B6%2C%E6%88%91%E4%B8%8D%E6%98%8E%E7%99%BD%E5%AE%83%E6%98%AF%E6%80%8E%E4%B9%88%E7%9C%8B%E5%87%BASn%E4%B8%8D%E4%B8%BA%E9%9B%B6%E7%9A%84%2C)
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