|4/1-2/1|+|6/1-4/1|+|8/1-6/1|+...+|2008/1-2006/1|=?
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|4/1-2/1|+|6/1-4/1|+|8/1-6/1|+...+|2008/1-2006/1|=?
|4/1-2/1|+|6/1-4/1|+|8/1-6/1|+...+|2008/1-2006/1|=?
|4/1-2/1|+|6/1-4/1|+|8/1-6/1|+...+|2008/1-2006/1|=?
楼主应该是打错了
分子和分母估计是弄反了
解答如下
首先去掉绝对值
1/2-1/4+1/4-1/6+1/6-1/8.+1/2006-1/2008
= 1/2-1/2008 因为中间的都抵消掉了
所以最后等于1003/2008
1/2*2-1+1/4*4-1+1/6*6-1+...+1/50*50-1
1,2,4,6,
|1/4-1/2|+|1/6-1/4|+|1/8-1/6|+```+|1/2008-1/2006|
1/2+1/4+1/6+1/8+.1/n
[2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)】/[1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)]
2/1+4/1+4/1+6/1+8/1+16/1+32/1=?
1+1+1+1+1+1+1+1+1+2+5+4+8+3+6+2+1+4等于多少?
巧算:(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)=====
1/2+1/2+4+1/2+4+6+.+1/2+4+6+...+100
(1- 1/100)(1- 1/99) .....(1- 1/4)(1- 1/3)(1- 1/2) (-1 1/2)*(-1 1/3)*......(-1 1/6)*(-1 1/7)
1+1/2+4+1/2+4+6+1/2+4+6+8+.+1/2+4+6+8...+20
4,2,1,1/2,1/4,( ) ( ) ( )1/8,1/32,1/4 ,1/16( )( ) ( )1/2,1/6,1/12,1/20,1/30,1/42 ( ) ( ) ( )
计算 1/2*4+1/4*6+.1/2006*2008
1/2*4+1/4*6+...+1/2012*2014=?
1/2*4+1/4*6+.+1/2008*2010
(1/4+1/2+1/6)×1/24等于什么?
简算:24×(1/2+1/3-1/4-1/6)
(1/2+1/3+1/4+1/6)*24