已知圆C:x2+y2-8y+12=0,直线l:ax+y+2a=0,当a为何值时,直线l与圆C相切,照理说有两解,为什么实际解出来只有一解
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![已知圆C:x2+y2-8y+12=0,直线l:ax+y+2a=0,当a为何值时,直线l与圆C相切,照理说有两解,为什么实际解出来只有一解](/uploads/image/z/1765143-63-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86C%3Ax2%2By2-8y%2B12%3D0%2C%E7%9B%B4%E7%BA%BFl%3Aax%2By%2B2a%3D0%2C%E5%BD%93a%E4%B8%BA%E4%BD%95%E5%80%BC%E6%97%B6%2C%E7%9B%B4%E7%BA%BFl%E4%B8%8E%E5%9C%86C%E7%9B%B8%E5%88%87%2C%E7%85%A7%E7%90%86%E8%AF%B4%E6%9C%89%E4%B8%A4%E8%A7%A3%2C%E4%B8%BA%E4%BB%80%E4%B9%88%E5%AE%9E%E9%99%85%E8%A7%A3%E5%87%BA%E6%9D%A5%E5%8F%AA%E6%9C%89%E4%B8%80%E8%A7%A3)
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