函数f(x)=x²-11x+30+a有两个不同零点均大于5,求实数a的取值范围
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 15:45:05
![函数f(x)=x²-11x+30+a有两个不同零点均大于5,求实数a的取值范围](/uploads/image/z/1767896-8-6.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3Dx%26%23178%3B-11x%2B30%2Ba%E6%9C%89%E4%B8%A4%E4%B8%AA%E4%B8%8D%E5%90%8C%E9%9B%B6%E7%82%B9%E5%9D%87%E5%A4%A7%E4%BA%8E5%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
xU[S@+;әTlJ7Oq&v}#"EQV+@K#0'BI9[x^&-knJEԧOoυiڏYa$ӫblllJ3Vi\m["m5+qÏ%͊6EM>Y`EpJ(%]V{f/E@KbT!.fխѲD;#F!gE
qY@vhEU0.xZeL?QB;cţf3Z/1bbBuAfoME#Ie *JXKI`M>7fKi(4'O.O} ȱ7p(e\c)aU`([U_|iUAQ&R);݆qNxK fv&'Wt[Rq(㮔~=+DF#a{}70NQ