如图,平行四边形ABCD的对角线AC、BD相交于点O,点E、F分别是OB、OD的中点.过点O任作一直线分别交AB、CD于点G、H.求证:GF平行EH.第一个回答滴 ∴△ABO≌△COD(ASA)∴GO=HO(全等三角形对应边相等
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![如图,平行四边形ABCD的对角线AC、BD相交于点O,点E、F分别是OB、OD的中点.过点O任作一直线分别交AB、CD于点G、H.求证:GF平行EH.第一个回答滴 ∴△ABO≌△COD(ASA)∴GO=HO(全等三角形对应边相等](/uploads/image/z/1770706-10-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E7%9A%84%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E3%80%81BD%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C%E7%82%B9E%E3%80%81F%E5%88%86%E5%88%AB%E6%98%AFOB%E3%80%81OD%E7%9A%84%E4%B8%AD%E7%82%B9.%E8%BF%87%E7%82%B9O%E4%BB%BB%E4%BD%9C%E4%B8%80%E7%9B%B4%E7%BA%BF%E5%88%86%E5%88%AB%E4%BA%A4AB%E3%80%81CD%E4%BA%8E%E7%82%B9G%E3%80%81H.%E6%B1%82%E8%AF%81%EF%BC%9AGF%E5%B9%B3%E8%A1%8CEH.%E7%AC%AC%E4%B8%80%E4%B8%AA%E5%9B%9E%E7%AD%94%E6%BB%B4+%E2%88%B4%E2%96%B3ABO%E2%89%8C%E2%96%B3COD%EF%BC%88ASA%EF%BC%89%E2%88%B4GO%3DHO%EF%BC%88%E5%85%A8%E7%AD%89%E4%B8%89%E8%A7%92%E5%BD%A2%E5%AF%B9%E5%BA%94%E8%BE%B9%E7%9B%B8%E7%AD%89)
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