设一元二次方程ax^2+bx+c=0(a≠0)的两根为x1,x2,则两根与方程系数之间有如下关系:x1+x2=-b/a,x1*x2=c/a,根据已知材料解答下面的问题:已知x1,x2是方程x^2-2x+a=0的两个实数根,且x1+2x2=3-根号2.(1)求x
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![设一元二次方程ax^2+bx+c=0(a≠0)的两根为x1,x2,则两根与方程系数之间有如下关系:x1+x2=-b/a,x1*x2=c/a,根据已知材料解答下面的问题:已知x1,x2是方程x^2-2x+a=0的两个实数根,且x1+2x2=3-根号2.(1)求x](/uploads/image/z/1772629-61-9.jpg?t=%E8%AE%BE%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bax%5E2%2Bbx%2Bc%3D0%28a%E2%89%A00%EF%BC%89%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%B8%BAx1%2Cx2%2C%E5%88%99%E4%B8%A4%E6%A0%B9%E4%B8%8E%E6%96%B9%E7%A8%8B%E7%B3%BB%E6%95%B0%E4%B9%8B%E9%97%B4%E6%9C%89%E5%A6%82%E4%B8%8B%E5%85%B3%E7%B3%BB%EF%BC%9Ax1%2Bx2%3D-b%2Fa%2Cx1%2Ax2%3Dc%2Fa%2C%E6%A0%B9%E6%8D%AE%E5%B7%B2%E7%9F%A5%E6%9D%90%E6%96%99%E8%A7%A3%E7%AD%94%E4%B8%8B%E9%9D%A2%E7%9A%84%E9%97%AE%E9%A2%98%EF%BC%9A%E5%B7%B2%E7%9F%A5x1%2Cx2%E6%98%AF%E6%96%B9%E7%A8%8Bx%5E2-2x%2Ba%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9%2C%E4%B8%94x1%2B2x2%3D3-%E6%A0%B9%E5%8F%B72.%EF%BC%881%EF%BC%89%E6%B1%82x)
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