2sin²(π/4+B/2)=1-cos(π/2+B)如何推导
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2sin²(π/4+B/2)=1-cos(π/2+B)如何推导
2sin²(π/4+B/2)=1-cos(π/2+B)如何推导
2sin²(π/4+B/2)=1-cos(π/2+B)如何推导
利用二倍角公式cos2A=1-2sin²A的变形公式:2sin²A=1-cos2A
令A=π/4+B/2
即得:2sin²(π/4+B/2)=1-cos(π/2+B)